Question

interpole doze meios aritméticos entre -3/4 e 11/6 urgeeeente me ajude em? ??​

Answer 1

-¾, _, _, _, _, _, _, _, _, _, _, _, _, 11/6

a₁=-¾

a₁₄=11/6

a₁₄=a₁+13r

$\frac{11}{6} = - \frac{3}{4} + 13r \\ \frac{22 = - 9 + 156r}{12} \\ 156r - 9 = 22 \\ 156r = 22 + 9$

$156r = 31 \\ r = \frac{31}{156}$

Agora basta ir somando a razão a cada termo.

-¾,-43/78,-55/156, -2/13, 7/156, 19/78,23/52,25/39,131/156,27/26,

193/156,56/39,85/52,11/6