Question

interpole 9 meios aritméticos entre 2 e 32

Answer 1

.
$a_1=2 \\ a_n=32 \\ n=9+2=11 \\ \\ a_n=a_1+(n-1)r \\ \\ 32=2+(11-1)r \\ \\ 32=2+10r \\ \\ 32-2=10r \\ \\ 10r=30 \\ \\ r=30\div10 \\ \\ r=3$

$P.A.=(2,5,8,11,14,17,20,23,26,29,32)$

Answer 2

Encontrar a razão:
an = a1 + ( n -1) * r
32 = 2 + ( 11 -1) * r
32 = 2 + 10*r
30 = 10*r  
r = 3 

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n  an = a1 + ( n -1) * r   an
1  an = 2 + ( 1 -1) *3     2
2  an = 2 + ( 2 -1) *3     5
3  an = 2 + ( 3 -1) *3     8
4  an = 2 + ( 4 -1) *3    11
5  an = 2 + ( 5 -1) *3    14
6  an = 2 + ( 6 -1) *3    17
7  an = 2 + ( 7 -1) *3     20
8  an = 2 + ( 8 -1) *3     23
9  an = 2 + ( 9 -1) *3     26
10 an = 2 + ( 10 -1) *3   29 
11 an = 2 + ( 11 -1) *3   32

PA = {2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32,}