Question

Interpole 10 meios aritméticos entre (-2) e 79.

Answer 1

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A P.A. tem 12 termos ; a1 = -2   e  a12 = 79

79 = -2 + (12-1)*r ⇒11r=81 ⇒ r = 81/11

$( - \frac{22}{11} , \frac{59}{11}, \frac{140}{11}, \frac{221}{11}, \frac{302}{11}, \frac{383}{11}, \frac{464}{11}, \frac{545}{11}, \frac{626}{11}, \frac{707}{11}, \frac{788}{11}, \frac{869}{11} ) \\ \\ ( - 2 , \frac{59}{11}, \frac{140}{11}, \frac{221}{11}, \frac{302}{11}, \frac{383}{11}, \frac{464}{11}, \frac{545}{11}, \frac{626}{11}, \frac{707}{11}, \frac{788}{11},79 )$