Question

Integral definida de

-pi/2 até pi/2 (8t^2 + cos (t)) dt

Answer 1

π/2

∫    8t² + cos (t)    dt
-π/2

                          π/2
[  (8/3) *t³ +sen(t)]    =(8/3)*(π/2)³ + sen(π/2) - (8/3)*(-π/2)³ - sen(-π/2) 
                        -π/2

2*8π³/3 +2

=2*(8π³/3 +1)

=(2/3)* (8π³+3)

=22,67