Question

Integral. Anexo do gráfico.

Answer 1

O coeficiente angular dessa reta é 2, portanto:

$y-y_0=m(x-x_0)\\\\y-0=2(x-0)\\\\v(x)=2x\\\\s(x)=\int v(x)dx \ +s(0)\\\\s(x)=\int2x.dx \ +5\\\\s(x)=2\int x.dx \ +5\\\\s(x)=2.\frac{x^2}{2}+5\\\\s(x)=x^2+5$