Question

insira dezoito meios aritméticos entre 7 e 64​

Answer 1

Resposta:

P.A. ( 7, 10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43, 46, 49, 52, 55, 58, 61, 64 ).

Explicação passo-a-passo:

an ⇒ a₂₀ = 64

a₁ = 7

n = 20

r = ?

an = a₁ + (n - 1) * r

64 = 7 + (20 - 1) * r

64 = 7 + 19r

19r = 64 - 7

19r = 57

r = 57/19

r = 3

P.A. ( 7, 10, 13, 16, 19, 22, 25, 28, 31, 34, 37, 40, 43, 46, 49, 52, 55, 58, 61, 64 ).