Question

Inserir dez meios aritméticos entre 7 e 62

Answer 1

a_1 = 7
a_10 = 62

a_10 = a_1 + 9*r <=> r = (62-7)/9  = 55/9 = 6 + 1/9

Termos 7,  13+1/9, 19+2/9, 25+3/9, 31+4/9, 37+5/9, 43+6/9, 49+7/9, 55+8/9, 62