Question

(Inatel-MG) O quociente de 8^(3x-4) por √4^(2-x) é: 

Answer 1

Espero que esteja certo, confira por favor. Ainda não dormir corre um grande risco, rs;

Answer 2

$\frac{8^{3x-4}}{\sqrt{4^{2-x}}}=\\\\\\\frac{(2^3)^{3x-4}}{(4^{2-x})^{\frac{1}{2}}}=\\\\\\\frac{2^{9x-12}}{(4)^{\frac{2-x}{2}}}=\\\\\\\frac{2^{9x-12}}{(2^2)^{\frac{2-x}{2}}}=\\\\\\\frac{2^{9x-12}}{2^{2-x}}=\\\\2^{9x-12-(2-x)}=\\\\\boxed{2^{10x-14}}$