Question

imagem preciso de ajuda com esses exercicios

Answer 1

a) (x-1)²=(x-1).(x-1)=x²-x-x+1=x²-2x+1
b) (a-2)²=(a-2).(a-2)=a²-2a-2a+4=a²-4a+4
c) (4x-1)²=(4x-1).(4x-1)=16x²-4x-4x+1=16x²-8x+1
d) (2a-5b)²=(2a-5b).(2a-5b)=4a²-10ab-10ab+25b²=4a²-20ab+25b²
e) (ab-c)²=(ab-c).(ab-c)=a²b²-abc-abc+c²=a²b²-2abc+c²
f) (x³-2)²=(x³-2).(x³-2)=x^6-2x³-2x³+4=x^6-4x³+4
g) (3x²-4)²=(3x²-4).(3x²-4)=9x^4-12x²-12x²+16=9x^4-24x²+16
h) (2x²-y²)²=(2x²-y²).(2x²-y²)=4x^4-2x²y²-2x²y²+y^4=4x^4-4x²y²+y^4

Answer 2

Boa noite Julia !
Solução

A)  $(x-1) ^{2} = x^{2} -2x+1$

B)  $(a-2) ^{2} = a^{2} -4a+4$ 

C)  $(4x-1) ^{2} =16 x^{2} -8x+1$ 

D)   $(2a-5b) ^{2} =4 a^{2} -20ab + 25b ^{2}$

E)   $(ab^{2}-c)^{2} = a^{2}b^{4} -2ab^{2} +c^{2}$ 

F)   $( x^{3}-2)^{2} = x^{6}-4 x^{3} +4$

G)  $(3 x^{2} - 4) ^{2}=9 x^{4} -24 x^{2} +16$

H)   $(2 x^{2} - y^{2})^{2} =4 x^{4}-4 x^{2} y^{2}+ y^{4}$


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