Question

I)x²-8x=0 II)x²-64=0

Answer 1

Resposta:

Explicação passo-a-passo:

I) Δ≈b²-4ac

x=-b±√Δ / 2a

x²-8x=0

Δ=(-8)²-4*1*0

Δ=64-0 = 64

x=-(-8)±√64 / 2*1

x=8±8/2

x1 = 16/2 = 8

x2=0/2 = 0

II) x²-64=0

x²=64

x=√64

x=8