Question

I = 2/3 . log de 10 na base 7.10^2.4 / 7.10^-3

Answer 1

2/3 log 10 (x/7.10-³)=6 

2/3 [log x - log 7.10-³]=6 

[log x - log 7.10-³]=6*3/2 

[log x - (log 7+ log 10-³)]=9 

log x -log 7 + 3log 10=9 
log x/7 + 3 = 9 

log x/7 = 6 

x/7=10^6 

x=7*10^6 

Letra B 


Não esqueça 

log a/b=log a -log b 
log a*b= log a +log b 

log a^b=b log a 

log a^(-b)=-b log a