Question

help por favor!!!!!!!!!!!!!!!!!!​

Answer 1

Resposta:

$cos(x) = \frac{\sqrt{77} }{9} \\\\tg(x) = \frac{2}{\sqrt{77}}$

Explicação passo-a-passo:

O = cateto OPOSTO

h = hipotenusa

A = cateto ADJACENTE

$cos(x) = \frac{2}{9} \\\frac{2}{9} => \frac{2x}{9x}\\\frac{2x}{9x} => \frac{O}{h} => O = 2x; h = 9x$

$h^2 = O^2 + A^2 => (9x)^2 = (2x)^2 + A^2\\81x^2 = 4x^2 + A^2\\A^2 = 77x^2\\\sqrt{A^2 = 77x^2} \\A = \sqrt{77x^2} \\A = x\sqrt{77}$

$Tg(x) = \frac{O}{A} => Tg(x) = \frac{2x}{x\sqrt{77}} => tg(x) = \frac{2}{\sqrt{77} }$

$cos(x) = \frac{A}{h} => \frac{x\sqrt{77} }{9x} => \frac{\sqrt{77} }{9}$