Question

gostaria de saber se está certo:

Answer 1

$A= \sqrt[3]{29- \sqrt[3]{6+ \sqrt[3]{8} } }\\A=\sqrt[3]{29- \sqrt[3]{6+ \sqrt[3]{2^3} } }\\A=\sqrt[3]{29- \sqrt[3]{6+2} }\\A=\sqrt[3]{29- \sqrt[3]{8} }\\A=\sqrt[3]{29- \sqrt[3]{2^3} }\\A=\sqrt[3]{29-2}\\A=\sqrt[3]{27}\\A=\sqrt[3]{3^3}\\\boxed{A=3}$

$B= \sqrt{21+ \sqrt{19- \sqrt{9} } }\\B= \sqrt{21+ \sqrt{19- \sqrt{3^2} } }\\B= \sqrt{21+ \sqrt{19-3} }\\B= \sqrt{21+ \sqrt{16} }\\B= \sqrt{21+ \sqrt{4^2} }\\B= \sqrt{21+4}\\B= \sqrt{25}\\B= \sqrt{5^2}\\\boxed{B=5}$

$\sqrt{A^3+B^2}= \sqrt{3^3+5^2}=\sqrt{27+25}=\sqrt{52}=\sqrt{2^2\cdot13}=\boxed{2\sqrt{13}}$

Alternativa D