Question

gostaria de saber :determine o oitavo termo da PG na qual A4=12 e q=2

Answer 1

$a_{n} = a_{1} * q^{n - 1}$
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$a_{n} = a_{1} * q^{n - 1}$
$a_{4} = a_{1} * q^{4 - 1}$
$a_{4} = a_{1} * q^{3}$
$12 = a_{1} * 2^{3}$
$12 = a_{1} * 8$
$\frac{12}{8} = a_{1}$

$a_{1} = \frac{3}{2}$

$a_{8} = a_{1} * q^{8 - 1}$
$a_{8} = a_{1} * q^{7}$
$a_{8} = \frac{3}{2} * 2^{7}$
$a_{8} = 3 * 2^{7 - 1}$
$a_{8} = 3 * 2^{6}$
$a_{8} = 3 * 64$
$a_{8} = 192$