Question

Gostaria de saber como resolver essas três questões com exatidão e qual a fórmula como começar

Answer 1

$\frac{3k-3}{2}=\frac{2k-1}{5}\\\\5*(3k-3)=2*(2k-1)\\\\15k-15=4k-2\\\\15k-4k=-2+15\\\\11k=13\\\\k=\frac{13}{11}$


$\frac{12m-4}{3}+\frac{m}{3}=\frac{1}{2}\\\\\frac{12m-4+m}{3}=\frac{1}{2}\\\\\frac{13m-4}{3}=\frac{1}{2}\\\\2*(13m-4)=3*1\\\\26m-8=3\\\\26m=3+8\\\\26m=11\\\\m=\frac{11}{26}$


$\frac{5p-2}{2}=\frac{p-1}{4}\\\\4*(5p-2)=2*(p-1)\\\\20p-8=2p-2\\\\20p-2p=-2+8\\\\18p=6\\\\p=\frac{6}{18}\\\\p=\frac{1}{3}$