Question

genteeeee me ajudem. Encontre a fração geratriz das seguintes dízimas: a)0,777... b)2,121212...

Answer 1

$a) 0,777...= \frac{7}{9} \\ \\ b) 2,121212... = 2+0,121212...=2+ \frac{12}{99} =\frac{198}{99} +\frac{12}{99} =\frac{198+12}{99}=\frac{210^{:3}}{99_{:3}}\\ \frac{210^{:3}}{99_{:3}} = \frac{70}{33}$