Question

gente por favor me ajudem
CALCULE:
A) (2xy)^3:(-8xy)^2
B) (-2a^4).(0,6a^2)
C) (-am^5 x^3)^6

Answer 1

A) $8 x^{3} y^{3}$ ÷ $64 x^{2} y^{2}$ =
$\frac{1}{8}xy$
B) $-2a^{4} .0,6 a^{2}$ =
$-1,2 a^{6} = - \frac{6}{5} a^{2}$
C) $(-a m^{5} x^{3})^{6} =$
$a^{6} m^{30} x^{18}$