Question

gente me ajudem!!! (x+3)^2=1

Answer 1

(x+3) . (x+3) = 1
x*2 +3x + 3x +9 -1=0
x*2 +6x +8 =0 agora resolve pela formula de bhaskara

x= -6 +- √6*2 -4.1.8 / 2.1
x= -6 +- √4 / 2
x= -6 +- 2 / 2
x1= -6 +2 /2 ⇒ -4/2 ⇒ -2
x2= -6 -2 /2 ⇒ -8/2 ⇒  -4