Question

gente me ajudam nessas contas aqui pfv ​

Answer 1

Olá!

Vamos aos cálculos:

b) (5xy) · (2$x^{2}$$y^{3}$)

5 · 2 = 10

xy · $x^{2}$$y^{3}$ =

x · $x^{2}$ · y · $y^{3}$ =

$x^{(1+2)}$ · $y^{(1+3)}$ =

$x^{3}$ · $y^{4}$ =

10 · $x^{3}$ · $y^{4}$ =

$10x^{3}y^{4}$

d) $(7xy^{2} )^{2}$ · $(x^{3}y^{2} )^{4}$

$7x^{(1.2)}y^{(2.2)}$ · $x^{(3.4)}$$y^{2.4}$ =

$7x^{2}y^{4}$ · $x^{12}y^{8}$ =

$7x^{(2+12)}y^{(4+8)}$ =

$7x^{14}y^{12}$

f) $\frac{2^{8}.5^{10} }{2^{5}.5^{6} }$

$2^{(8-5)}$ · $5^{(10-6)}$ =

$2^{3}$ · $5^{4}$ =

8 · 625 =

5000

Abraços!