Question

gente me ajuda por favor ​

Answer 1

Resposta:

a) x' = 2; x'' = 2

b) x' = -3; x'' = -3

c) x' = 1; x'' = 1

d) x' = 2; x'' = 2

e) x' = -3; x'' = -3

Explicação passo a passo:

a) 2$x^{2}$ - 8x + 8 = 0

a = 2; b = -8; c = 8

Δ = $b^{2}$ - 4ac

Δ = $-8^{2}$ - 4 . 2 . 8

Δ = 64 - 64

Δ = 0

x = -b ± $\sqrt{delta}$

          2a

x = -(-8) ± $\sqrt{0}$

        2 . 2

x = 8 ± 0

        4

x' = $\frac{8+0}{4}$

x' = $\frac{8}{4}$

x' = 2

x'' = $\frac{8-0}{4}$

x'' = $\frac{8}{4}$

x'' = 2

b) 2$x^{2}$ + 12x + 18 = 0

a = 2; b = 12; c = 18

Δ = $b^{2}$ - 4ac

Δ = $12^{2}$ - 4 . 2 . 18

Δ = 144 - 144

Δ = 0

x = -b ± $\sqrt{delta}$

          2a

x = -12 ± $\sqrt{0}$

        2 . 2

x = -12 ± 0

        4

x' = $\frac{(-12)+0}{4}$

x' = $\frac{-12}{4}$

x' = -3

x'' = $\frac{(-12)-0}{4}$

x'' = $\frac{-12}{4}$

x'' = -3

c) 2$x^{2}$ - 4x + 2 = 0

a = 2; b = -4; c = 2

Δ = $b^{2}$ - 4ac

Δ = $-4^{2}$ - 4 . 2 . 2

Δ = 16 - 16

Δ = 0

x = -b ± $\sqrt{delta}$

          2a

x = -(-4) ± $\sqrt{0}$

        2 . 2

x = 4 ± 0

        4

x' = $\frac{4+0}{4}$

x' = $\frac{4}{4}$

x' = 1

x'' = $\frac{4-0}{4}$

x'' = $\frac{4}{4}$

x'' = 1

d) 4$x^{2}$ - 16x + 16 = 0

a = 4; b = -16; c = 16

Δ = $b^{2}$ - 4ac

Δ = $-16^{2}$ - 4 . 4 . 16

Δ = 256 - 256

Δ = 0

x = -b ± $\sqrt{delta}$

          2a

x = -(-16) ± $\sqrt{0}$

        2 . 4

x = 16 ± 0

        8

x' = $\frac{16+0}{8}$

x' = $\frac{16}{8}$

x' = 2

x'' = $\frac{16-0}{8}$

x'' = $\frac{16}{8}$

x'' = 2

e) $x^{2}$ + 6x + 9 = 0

a = 1; b = 6; c = 9

Δ = $b^{2}$ - 4ac

Δ = $6^{2}$ - 4 . 1 . 9

Δ = 36 - 36

Δ = 0

x = -b ± $\sqrt{delta}$

          2a

x = -6 ± $\sqrt{0}$

      2 . 1

x = -6 ± 0

        2

x' = $\frac{-6+0}{2}$

x' = $\frac{-6}{2}$

x' = -3

x'' = $\frac{-6-0}{2}$

x'' = $\frac{-6}{2}$

x'' = -3

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Espero ter ajudado!!!

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