Question

GENTE ME AJUDA PFVR


20 S


a)2.√1/9 + √16 /36 =


b)3.√1/49 - √4/49 =


c)2³√27 - ∛8/64

------------ =

√64


d) √1/4 . 1/9 - √4/49 =

Answer 1

$a)\\ \\ 2.\sqrt{\frac{1}{9}} +\sqrt{\frac{16}{36}} =\\ \\ 2.\frac{1}{3} +\frac{4}{6} =\\ \\ \frac{2}{3} +\frac{4}{6} \\ \\ mmc=6\\ \\ \frac{4+4}{6} =\frac{8}{6} =\frac{4}{3}$

$b)\\ \\ 3.\sqrt{\frac{1}{49}} -\sqrt{\frac{4}{49}} =\\ \\ 3.\frac{1}{7} -\frac{2}{7} =\\ \\ \frac{3}{7} -\frac{2}{7} =\frac{1}{7} \\ \\ c)\\ \\ 2.\sqrt[3]{27} -\sqrt[3]{\frac{8}{64}} =\\ \\ 2.3-\frac{2}{4} =\\ \\ 6-\frac{2}{4} =\\ \\ mmc=4\\ \\ \frac{24-2}{4} =\frac{22}{4}=\frac{11}{2}$

$d)\\ \\ \sqrt{\frac{1}{4}} ~.~\frac{1}{9} -\frac{2}{7} =\\ \\ \frac{1}{2} .\frac{1}{9} -\frac{2}{7} =\frac{1}{18} -\frac{2}{7} =\\ \\ mmc=126\\ \\ \frac{7-36}{126} =\frac{29}{126}$