Question

g)x²=2x+8
h)6x=-x²-5​

Answer 1

$g)\\ x^2=2x+8\\ x^{2} -2x-8=0\\ \\ a=1\\ b=-2\\ c=-8\\ \\ \Delta=b^2-4ac\\ \Delta=(-2)^2-4(1)(-8)\\ \Delta=4+32\\ \Delta=36\\ \\ x={-b\pm\sqrt{\Delta} \over2a}={-(-2)\pm\sqrt{36} \over2}={2\pm6\over2}\\ \\ x'={2+6\over2}={8\over2}=4\\ \\ x"={2-6\over2}=-{4\over2}=-2\\ \\ S=\{-2,4\}$

$h)\\ 6x=-x^2-5\\ x^2+6x+5=0\\ \\ a=1\\ b=6\\ c=5\\ \\ \Delta=b^2-4ac\\ \Delta=6^2-4(1)(5)\\ \Delta=36-20\\ \Delta=16\\ \\ x={-6\pm\sqrt{16} \over2}={-6\pm4\over2}\\ \\ x'={-6-4\over2}=-{10\over2}=-5\\ \\ x"={-6+4\over2}=-{2\over2}=-1\\ \\ S=\{-5,-1\}$