Question

Função Matematica:

Se $f(x) = \frac{x^4+x^2}{x+1}$, então $f ( \frac{1}{2} )$ é:

A) $\frac{5}{24}$

B) $- \frac{5}{32}$

C) $\frac{5}{32}$

D) $\frac{5}{8}$

Answer 1

$Resolu{c}\~ao \to \left\{\begin{array}{ccc}f(x) = \frac{x^4+x^2}{x+1} \\\\f( \frac{1}{2} ) = \frac{( \frac{1}{2} )^4+( \frac{1}{2} )^2}{ \frac{1}{2} +1}\\\\f( \frac{1}{2}) = \frac{ \frac{1}{16} + \frac{1}{4} }{ \frac{1+2}{2} }\\\\f( \frac{1}{2}) = \frac{ \frac{1+4}{16} }{ \frac{3}{2} } = \frac{5}{16}* \frac{2}{3}\\\\\boxed{\boxed{f( \frac{1}{2}) = \frac{10}{48} = \frac{5}{24}}} \to Letra A \end{array}\right$

Espero ter ajudado. :))