Question

função exponencial resolva:1) 4^x-9*2^x+8=02)9^x-4*3^x+3=0

Answer 1

${4}^{x} - 9 . {2}^{x} + 8 = 0 \\ 2.{2}^{x} - 9. {2}^{x} = - 8 \\ (2 - 9). {2}^{x} = - 8 \\ - 7. {2}^{x} = - 8 \\ {2}^{x} = \frac{ - 8}{ - 7} \\ x = log( \frac{8}{7} )$