Question

função exponencial me ajudemmm pfvvv

Answer 1

Vamos lá:

Lembrete:

$a^0=1$

$a^{-b}=\left(\frac{1}{a}\right)^b$
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b) 
$\left(27^{\frac{1}{3}}+64^{\frac{1}{2}}-8^{\frac{2}{3}}+4^{\frac{1}{2}}\right)^{\frac{1}{2}}\\\left(\sqrt[3]{27}+\sqrt{64}-\sqrt[3]{8^2}+\sqrt{4}\right)^{\frac{1}{2}}\\\left(3+8-4+2\right)^{\frac{1}{2}}\\9^{\frac{1}{2}}=\sqrt{9}=3$
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c)
$\frac{3^0+\left(-2\right)^2-\left(\frac{1}{3}\right)^{-1}}{\left(\frac{1}{2}\right)^{-2}}\\\frac{1+4-3}{2^2}=\frac{2}{2^2}=\frac{1}{2}=2^{-1}$
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Espero ter ajudado!