Question

função exponencial.. me ajudem pfvvv

Answer 1

Vamos lá:

Lembrete:

$\sqrt[b]{a^c}=a^{\frac{c}{b}}$
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$\left(27^{\frac{1}{3}}+64^{\frac{1}{2}}-8^{\frac{2}{3}}+4^{\frac{1}{2}}\right)^{\frac{1}{2}}\\ \left(\sqrt[3]{27^1}+\:\sqrt[2]{64^1}\:-\:\sqrt[3]{8^2}+\:\sqrt[2]{4^1}\right)^{\frac{1}{2}} \\\left(\sqrt[3]{27}+\:\sqrt{64}\:-\:\sqrt[3]{8^2}+\sqrt{4}\right)^{\frac{1}{2}}\\\left(3+8-\sqrt[3]{64}+2\right)^{\frac{1}{2}}\\(3+8-8+2)^{\frac{1}{2}}\\5^{\frac{1}{2}}= \sqrt{5}$
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Espero ter ajudado!