Question

Fórmula de bhaskara X''+5X+4=0

Answer 1

x²+5x+4 = 0

Aplica-se Delta:
Δ = 5²-4.1.4
Δ = 25-16
Δ = 9

Aplica-se Bhaskara:
-5 +- √9/2.1
-5+-3/2

x' = -5+3/2 = -1
x'' = -5-3/2 = -4

Answer 2

X^2 + 5X + 4 = 0
a=1; b = 5; c = 4
∆ = b^2-4ac
∆ = 5^2 - 4.1.4
∆ = 25-16
∆ =9

x = [-b +/- √∆]/2a
x = [- 5 +/- √9]/2.1
x' = [-5 +3]/2 = -2/2 = - 1
x" = [-5 -3]/2 = -8/2 = - 4

R. (- 1; - 4)