Question

Formula de Baskara (Para Agora Me Ajude!)

2x²-4x-1=0

(formula completa, e certa)

Answer 1

$2x^2 - 4x - 1 = 0$

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Encontrar o valor de Delta (Δ)

Δ=b²−4ac
Δ=(−4)²−4⋅2⋅−1
Δ=16+8
Δ=24

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$x = \dfrac{-b \pm \sqrt{\Delta}}{2*a}\\ \\ \\ x = \dfrac{-(-4) \pm \sqrt{24}}{2*2}\\ \\ \\ x = \dfrac{4 \pm 2\sqrt{6}}{4}\\ \\ \\ x' = \dfrac{4 + 2\sqrt{6}}{4}\\ \\ \\ x' = \dfrac{2 + \sqrt{6}}{2}\\ \\ \\x'' = \dfrac{4 -2\sqrt{6}}{4}\\ \\ \\x'' = \dfrac{2 - \sqrt{6}}{2}$


S = ( $\dfrac{2 + \sqrt{6}}{2}, ~~ \dfrac{2 - \sqrt{6}}{2}$ )