Question

Forma de bhaskara 9) 3x² - 20 = x² - 2

Answer 1

Resposta:

$3x^{2}-20=x^{2} -2\\3x^{2} -x^{2} -20+2=0\\2x^{2} -18=0\\D=b^{2}-4ac\\ D=0-4.2.(-18)\\D=144\\x_{1}=\frac{-b+\sqrt{D} }{2.a}; ou; x_{2}=\frac{-b-\sqrt{D} }{2.a} \\x_{1}=\frac{\sqrt{144} }{4}; ou; x_{2}=-\frac{\sqrt{144} }{4} \\x_{1}=\frac{12}{4}; ou; x_{2}=-\frac{12}{4} \\x_{1}=3; ou; x_{2}=-3$

Explicação passo-a-passo: