Question

Fatore por agrupamento:
a) ax – ay + bx – by =
b) 5ax – 5ay + bx – by =
c) x² + 5x + ax + 5a =
d) 6ª² + 2ab – 3ac – bc =
e) t³ + t² – 7t – 7 =

Answer 1

Resposta:

Explicação passo a passo:

a) ax – ay + bx – by => a(x - y) + b( x - y) => (a + b)( x - y)

b) 5ax – 5ay + bx – by => 5a( x - y) + b(x - y) => (5a + b)(x - y)  

c) x² + 5x + ax + 5a => x(x +5) + a(x + 5) => (x + a) (x + 5)

d) 6ª² + 2ab – 3ac – bc => 2a( 3a + b) - c( 3a + b) => (2a - c)( 3a + b)

e) t³ + t² – 7t – 7 => t²( t + 1) - 7(t + 1) => (t² - 7)(t + 1)