Question

fatorando o agrupamento: (ab+ac+3b+3c) obtemos:​

Answer 1

Resposta:

.    (b + c).(a + 3)

Explicação passo a passo:

.

.      ab  +  ac  +  3b  +  3c  =  a . (b  +  c)  +  3 . (b  +  c)

.                                            =  (b  +  c).(a  +  3)

.

(Espero ter colaborado)

Answer 2

Resposta:

$ab+ac+3b+3c\\\\\mathrm{Fatorar\:o\:termo\:comum\:}a\\\\=a\left(b+c\right)+3b+3c\\\\\mathrm{Fatorar\:o\:termo\:comum\:}3\\\\=a\left(b+c\right)+3\left(b+c\right)\\\\\mathrm{Fatorar\:o\:termo\:comum\:}\left(b+c\right)\\\\=\left(b+c\right)\left(a+3\right)$