Question

fatoraçao

$<var>(4+2(32-1/4(2/3-1/8)+2)+16)+1</var>$

Answer 1

Façamos $\text{A}=\{4+2\cdot[32-\frac{1}{4}\left(\frac{2}{3}-\dfrac{1}{8}\right)+2]+16\}+1$

 

Desta maneira, temos:

 

$\text{A}=\{4+2\cdot[32-\frac{1}{4}\cdot\dfrac{13}{24}+2]+16\}+1$

 

$\text{A}=\{4+2\cdot[32-\frac{13}{96}+2]+16\}+1$

 

$\text{A}=\{4+2\cdot[\frac{3~072}{96}+2]+16\}+1$

 

$\text{A}=\{4+2\cdot34+16\}+1$

 

$\text{A}=88+1=89$