Question

Faça as alterações de temperatura:
a) 50° C em °F
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b) 10° C em °F
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c) -5° C em °F
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d) 100° C em °F
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e) -15° C em °F
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f) 80° C em °F
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g) -4° C em °F
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h) 0° C em °F
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i) -20° C em °F
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j) 25° C em °F
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Answer 1

Resposta:a) 122°f   b) 50°f  c) 23°f  d)212°f   e) 5°f   f)176°f  g) 24,8°f  h)32°f   i) -4°f   j) 77°f

Explicação:

a)Tc= 5(Tf-32)/9  b) 10=5(Tf-32)/9  c)-5=5(Tf-32)/9 d)100=5(Tf-32)/9

  50=5(Tf-32)/9     10/5=(Tf-32)/9    -5/5=(Tf-32)/9    100/5=(Tf-32)/9

  50/5=(Tf-32)/9     2x9=Tf-32           -1x9=Tf-32         20x9=Tf-32

  10x9=Tf-32           18+32=Tf             -9+32=Tf            180+32=Tf

  90+32= Tf             Tf=50°f                Tf=23°f              Tf=212°f

  Tf=122°f

e)-15=5(Tf-32)/9   f)80=5(Tf-32)/9   g)-4=5(Tf-32)/9  h)0=5(Tf-32)/9

  -15/5=(Tf-32)/9    80/5=(Tf-32)/9     -4x9=5(Tf-32)     0/5x9=Tf-32

  -3x9=Tf-32          16x9=Tf-32           -36/5=Tf-32       0+32= Tf

  -27+32=Tf           144+32=Tf            -7,2+32=Tf            Tf=32°f

  Tf=5                     Tf=176°f               Tf=24,8°f

i)-20=5(Tf-32)/9   j)25=5(Tf-32)/9

 -20x9=5(Tf-32)     25/5=(Tf-32)/9

 -180/5=Tf-32         5x9=Tf-32

 -36+32=Tf              45+32=Tf

   Tf=-4                     Tf=77°f

Answer 2

a) 100___180

50___ x-32

100(x -32) = 50×180

100x -3200 = 9000

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