Question

Faça a conta : $\frac{9^{3} . 27^{4} . 3^{-7} }{3^{-1}. 243^{2}} }$

Answer 1

$\frac{9^3\cdot27^4\cdot3^{-7}}{3^{-1}\cdot243^2} = \frac{(3^2)^3\cdot(3^3)^4\cdot3^{-7}}{3^{-1}\cdot(3^5)^2} = \frac{3^6\cdot3^{12}\cdot3^{-7}}{3^{-1}\cdot3^{10}} = \frac{3^{6+12+(-7)}}{3^{-1+10}} =\frac{3^{6+12-7}}{3^9} =\frac{3^{11}}{3^9} \\ =3^{11-9}=3^2=9$