Question

f(x) = -x² + 5x - 4 alguém pode me ensinar como achar o x1 e o x2 ? ​

Answer 1

Delta= b^2-4.a.c
Delta = 1-16
Delta= -15
Bhaskara= -b+- raiz de delta/2a
Bhaskarax1= 1+3,88/-2
Bhaskara x1= 4,88/-2
Bhaskara x1 = -2,44
Bhaskara x2= 1-3,88/-2
Bhaskara x2 = -1,44

Answer 2

fórmula de Bhaskara

$x = \frac{ - 5 + - \sqrt{ {5}^{2} - 4 \times ( - 1) \times ( - 4) } }{2 \times 1?} \\ x = \frac{ - 5 + - \sqrt{25 - 16} }{2} \\ x = \frac{ - 5 + - \sqrt{9} }{2} \\ x = \frac{ - 5 + - 3}{2} \\ x 1= \frac{ - 5 + 3}{2} = \frac{ - 2}{2} = - 1 \\ x2 = \frac{ - 5 - 3}{2} = \frac{ - 8}{2} = - 4$