Question

f(x) -X(ao quadrado)-2x+3

Answer 1

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f(x)=-x²-2x+3

a=-1
b=-2
c=3

Δ=b²-4ac
Δ=(-2)²-4(-1)(3)
Δ=4+12
Δ=16

$x= \frac{-b\pm \sqrt{\Delta} }{2a} =~~ \frac{-(-2)\pm \sqrt{16} }{-2} =~~ \frac{2\pm4}{-2} \\ \\ x'= \frac{2+4}{-2} = \frac{6}{-2} =-3 \\ \\ x"= \frac{2-4}{-2} = \frac{-4}{-2} =+2$

Answer 2

F(x) -x²-2x+3

a=-1
b=-2
c=3

∆=b²-4.a.c
∆=(-2)²-4.(-1).3
∆=4-4.3
∆=4+12
∆=16

x=-b±√16 / 2.a
x= 2±4 / 2.(-1)
x= 2±4 / -2

x'=2+4 / -2
x'=2+4= 6/-2 = -3

x''=2-4 / -2
x''= -2 / -2
x'' = 1

R {x'=-3 x''=1}