Question

f(x)=2x²-7x+3
atribuir os x para -2 , -1 , 0 , 1 , 2 e 3

Answer 1

$a) \\ \\ f(x) = 2 x^{2} -7x + 3 \\ \\ f(-2) = 2(-2)^2 - 7(-2) + 3 \\ \\ f(-2) = 8 + 14 + 3 \\ \\ f(-2) = 25$
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$b) \\ f(x) = 2 x^{2} -7x + 3 \\ \\ f(-1) = 2 (-1)^{2} -7(-1) + 3 \\ \\ f(x-1) = 2 +7 + 3 \\ \\ f(x-1) = 12$
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$c)f(x) = 2 x^{2} -7x + 3\\ \\ f(0) = 2 *(0)^2 -7 (0) + 3 \\ \\  f(0) = 3$
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$d) \\ f(x) = 2 x^{2} -7x + 3 \\ \\ f(2) = 2 *2^{2} -7*2 + 3 \\ \\  f(2) = 4 - 17 + 3 \\ \\ f(2) = -3$
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$e) \\ f(x) = 2 x^{2} -7x + 3 \\ \\ f(3) = 2 *3^{2} -7*3 + 3 \\ \\\f(3) = 18 - 21 + 3 \\ \\ f(3) = 18 - 18 \\ \\ f(3) = 0$