Question

esolva as seguintes equações,com a formula de Bhaskara.
a)$x^{2} -8x+14=0$

b)$x^{2} -12x+20=0$

Answer 1

a)x²-8x+14=0
Δ=(-8)²-4.1.14
Δ=64-56
Δ=8

x=8+-√8/2.1

x'=8+√8/2

x''=8-√8/2

b)x²-12x+20
Δ=(-12)²-4.1.20
Δ=144-80
Δ=64

x=12+-√64/2.1

x'=12+8/2
x'=10

x''=12-8/2
x''=2