Question

Escreva na forma de potência de base 2

$(- 0,5)^{-3}$

$0,16 X 10^{2}$

$16^{2} : 0,25^{3}$

$(-0,25^{2}) ^{-3}$

Answer 1

$(-0,5)^{-3} = ( - \frac{5}{10} ) ^{-3} = (- \frac{1}{2} ) ^{-3} = -2 ^{3} =$

$0,16 . 10^{2} = \frac{16}{100} .100 = \frac{1600}{100} = 16 = 2^{4}$

$\frac{ 16^{2} }{0,25 ^{3} } = \frac{(2^{4} )^2}{( \frac{25}{100})^3 } = \frac{2^8}{( \frac{1}{4})^3 } = \frac{2^8}{( \frac{1}{(2)^2})^3 }= \frac{2^8}{( 2^{-2} )^3} = \frac{ 2^{8} }{ (2^{-6}) }$=$2^{8-(-6)}= 2^{14$



$(( -0,25) ^{2} ) ^{-3} =((\frac{-25}{100}) ^{2} ) ^{-3} = ((\frac{-1}{4}) ^{2} )^{-3} =((\frac{-1}{ 2^{2} })^{2}){^{-3} } =((- 2)^{-2} )^{2}) ^{-3} =$=$2^{12}$