Question

escreva a P.A de cinco termos onde a1=7 e r=4

Answer 1

a₁ = 7     r = 4
$a_n=a_1+(n-1)\cdot r\\ \\a_1=7\\ \\a_2=7+(2-1)\cdot 4=7+1\cdot 4=7+4=11 \therefore\ a_2=11\\ \\a_3=7+(3-1)\cdot 4=7+2\cdot 4=7+8=15 \therefore\ a_3=15\\ \\a_4=7+(4-1)\cdot 4=7+3\cdot 4=7+12=19 \therefore\ a_4=19\\ \\a_5=7+(5-1)\cdot 4=7+4\cdot 4=7+16=23 \therefore\ a_5=23$

Answer 2

Informações:

a1= 7  r=4
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a1=7
a2= 7 + 4 =11
a3=11 + 4 = 15
a4=15 +4=19
a5=19+4=23

P.A=7,11,15,19,13.

Bons estudos :=)