Question

Escreva a equação geral da reta definida pelos pontos: A) a (-1,6) b(2,-3);
B) a (5,0) b (-1,-4)

Answer 1

A-)
m = (y2 – y1) / (x2 – x1)
m = -3 – 6 / 2 – (–1)
m = –9 / 3
m = –3

y – y1 = m (x – x1).
y – 6 = –3 (x + 1)
y – 6 = –3x – 3
y – 6 + 3x + 3 = 0
y + 3x – 3 = 0
3x + y – 3 = 0

B-)
m = (y2 – y1) / (x2 – x1)
m = -4 – 0 / -1 – 5
m = –4 / -6
m = 0,66

y – y1 = m (x – x1).
y – (-4) = 0,66(x + 1)
y +4 = 0.66x -0,66
y +4 -0,66x + 0,66 = 0
y -0,66x +4,66 = 0