Question

 equações exponenciais a seguir (1/2)x-1=16x+2

Answer 1

$\left(\frac{1}{2} \right) ^{x-1}=16^{x+2} \\ \\ 2^{-(x-1)}=\left(2^4\right)^{x+2} \\ \\ 2^{1-x}=2^{4x+8} \\ \\ 4x+8=1-x \\ \\ 4x+x=1-8 \\ \\ 5x=-7 \\ \\ x=-\frac{7}{5}$

Answer 2

$(\frac{1}{2})^{x-1}= 16^{x+2}\\ \\(2^{-1})^{x-1}=(2^{4})^{x+2}\\ \\\not{2}^{-x+1}=\not{2}^{4x+8}$

$-x+1=4x+8~(-1)\\x-1=-4x-8\\5x=-7\\ \\x=-\frac{7}{5}$