Question

Equação exponencial, Me ajudem​

Answer 1

Resposta:

i) x = 10

j) x = -6/5

Resolução:

i) 8^(x + 2) = 16^(x - 1)

(2^3)^(x + 2) = (2^4)^(x - 1)

2^(3x + 6) = 2^(4x - 4)

3x + 6 = 4x - 4

6 + 4 = 4x - 3x

10 = x

j) 49^(2x) = 343^(3x + 2)

(7^2)^(2x) = (7^3)^(3x + 2)

7^(4x) = 7^(9x + 6)

4x = 9x + 6

-6 = 9x - 4x

-6 = 5x

x = -6/5

Answer 2

i)

(2³)^(x+2)= (2^4)^(x-1)

3*(x+2)= 4*(x-1)

3x+6=4x-4

6+4=x

x=10

j)

(7²)^2x=(7³)^(3x+2)

2*(2x) =3*(3x+2)

4x=9x+6

9x-4x=-6

5x=-6

x=-6/5