Question

Equação exponencial:

3^x^2-10x+7=1/9

Answer 1

Resposta:

Se for 3^(x²-10x+7) =1/9

3^(x²-10x+7) =3⁻²

x²-10x+7=-2

x²-10x+9=0

x'= [10+√(100-36)]/2=(10+8)/2=9

x''= [10-√(100-36)]/2=(10-8)/2=1

Answer 2

Resposta:

3^(x²-10x+7) =1/9

3^(x²-10x+7) =3⁻²

x²-10x+7=-2

x²-10x+9=0

x'= [10+√(100-36)]/2=(10+8)/2=9

x''= [10-√(100-36)]/2=(10-8)/2=1