Question

Equaçao exponencial
3.4×+¹ =96

Answer 1

E aí Douglas,

dada a equação exponencial,

$3*4^{x+1}=96$

podemos fazer:

$4^{x+1}= \dfrac{96}{3}\\\\ (2^2)^{x+1}=32\\ 2^{2x+2}=2^5\\ \not2^{2x+2}=\not2^5\\\\ 2x+2=5\\ 2x=5-2\\ 2x=3\\\\ x= \dfrac{3}{2}\\\\\\ S=\left\{ \dfrac{3}{2}\right\}$

Espero ter ajudado vc cara, e tenha ótimos estudos =))

Answer 2

$3*4^{x+1}=96\\ \\ 4^{x+1}=\frac{96}{3}\\ \\ 4^{x+1}=32\\ \\ (2^2)^{x+1}=2^5\\ \\ 2^{2x+2}=2^5\\ \\ 2x+2=5\\ \\ 2x=3\\ \\ \boxed{x=\frac{3}{2}}$