Question

equação do 2 grau sendo U =IR
x²-4x+4=0

Answer 1

x² - 4x + 4 = 0

a = 1; b = -4; c = 4

x = [- b ± √(b² - 4ac)] / 2a
x = [- (-4) ± √([-4]² - 4 . 1 . 4)] / 2 . 1
x = [4 ± √(16 - 16)] / 2
x = [4 ± √0] / 2
x = [4 ± 0] / 2
x' = [4 + 0] / 2 = 4 / 2 = 2
x'' = [4 - 0] / 2 = 4 / 2 = 2

S = {2}

Espero ter ajudado. Valeu!

Answer 2

x² - 4x + 4 = 0

Δ = b²−4ac 
Δ = (−4)²−4⋅1⋅4
Δ = 16−16
Δ = 0


x = -b ± √Δ / 2.a

x = -(-4) ± √0 / 2.1
x = 4 - 0 / 2
x' = 4 / 2
x' = 2

x'' = 4 + 0 / 2
x'' = 4 / 2
x'' = 2

S = {2}