Question

equação da reta tangente ao grafico

seja f(x) = x5, calcule f"(x)

Answer 1

 Olá Bigodun,
boa tarde!
 
$f(x)=x^5\\\\f'(x)=5\cdot\,x^{5-1}\cdot1\\\\f'(x)=5x^4\\\\f''(x)=4\cdot5\cdot\,x^{4-1}\cdot1\\\\\boxed{f''(x)=20x^3}$

Answer 2

eja f(x) = x5, calcule f"(x)


f(x) = x5

f'(x) = x5 ==> f'(x) =  5x^4

f"(x) =  f'(x) =  20x^3