Question

Equação
6x^- 13x +5 =0

Answer 1

6x² - 13x + 5 = 0

a = 6
b = -13 
c = 5

$\frac{-b+- \sqrt{ b^{2} -4.a.c} }{2.a} = \frac{-(-13)+- \sqrt{ (-13)^{2} -4.6.5} }{2.6} =\frac{13+- \sqrt{ 169 -120} }{12} = \frac{13+- \sqrt{ 49} }{12} =$ 

$\frac{13+- 7 }{12}$

x' = $\frac{13+ 7 }{12}$ = 20/12 = 5/3
x'' = $\frac{13- 7 }{12}$ = 6/12 = 1/2