Question

equaçao 1.x2-9x+20=0

Answer 1

x² - 9x + 20 = 0

Δ = b² - 4ac
Δ = (- 9)² - 4.1.20
Δ = 81 - 80
Δ = 1

x = (- b) ± √Δ / 2a

x¹ = 9 + 1 / 2.1
x¹ = 10/ 2
x¹ = 5

x² = 9 - 1 / 2.1
x² = 8/ 2
x² = 4

S = {4, 5}

Espero ter ajudado!