Question

(EPCAR 2002). ajudem-me

Answer 1

$\sqrt{ \frac{x}{y} \sqrt[3]{ \frac{y}{x} } } = \sqrt{\sqrt[3]{ \frac{ x^{3} }{ y^{3} } .\frac{y}{x} } } = \sqrt[6]{ \frac{ x^{2} }{ y^{2} } }= \sqrt[3]{ \frac{x}{y} }$$= \frac{ \sqrt[3]{x} }{ \sqrt[3]{y} }$

O inverso será:

$\frac{ \sqrt[3]{y} }{ \sqrt[3]{x} }$$\frac{ \sqrt[3]{y} }{ \sqrt[3]{x} } =$$\frac{ \sqrt[3]{y} .\sqrt[3]{ x^{2} }}{ \sqrt[3]{x}.\sqrt[3]{ x^{2} } } =\frac{ \sqrt[3]{ x^{2}y }}{ x} }$

Letra b)